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2.2x^2-2.75x+0.825=0
a = 2.2; b = -2.75; c = +0.825;
Δ = b2-4ac
Δ = -2.752-4·2.2·0.825
Δ = 0.3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.75)-\sqrt{0.3025}}{2*2.2}=\frac{2.75-\sqrt{0.3025}}{4.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.75)+\sqrt{0.3025}}{2*2.2}=\frac{2.75+\sqrt{0.3025}}{4.4} $
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